This video show you how to use calculus to prove the volume formula for a pyramid with a square base using cross-sections and integration.
In this video, you'll see how to use Calculus to prove the volume formula for a Pyramid. By slicing the pyramid perpendicular to its height, each cross-section forms a square whose side length changes with x. Writing the area of each slice as a function of x and integrating from the vertex to the base shows why the pyramid volume formula is V = (1/3)Bh, where B is the area of the base and h is the height. This approach reinforces connections between geometry and integral calculus.
A pyramid’s volume can be derived using calculus and cross-sections.
The pyramid is positioned with its vertex at the origin and its height along the positive x-axis.
Each cross-section perpendicular to the x-axis is a square.
Similar triangles relate the side length of a square slice to its distance x from the vertex.
The side length of a slice is (base side length / height) times x.
The area of a slice is proportional to x squared.
Hey guys, Mr. Antonucci here, and we’re going to use calculus to prove the volume formula for a pyramid with a square base.