This video show you how to use calculus to prove the volume formula for a sphere using cross-sections and integration.
In this video, you'll that by placing the sphere on a coordinate plane and slicing it perpendicular to the x-axis, each cross-section becomes a circle. Using the equation of a circle, the radius of each slice is written as a function of x. Integrating the area of these circular slices from −R to R (or using symmetry from 0 to R) produces the familiar formula V = 4/3 πR³. This proof connects geometry, algebra, and integral calculus in a single argument.
The sphere is centered at the origin on the x–y coordinate plane.
The radius of the sphere is R, extending from −R to R on both axes.
Cross-sections perpendicular to the x-axis are circles.
The radius of each circular slice is given by the y-value at that x.
The equation x² + y² = R² is used to write y in terms of x.
The area of each cross-section is π(R² − x²).
All right guys, Mr. Antonucci here, and in this video we’re going to prove the formula for the volume of a sphere using calculus.